I want to arrange the elements of the Swift array in alphabetical order.

Asked 2 months ago, Updated 2 months ago, 1 views

["Sato", "Aoki", "Ono"] and other array with the name string
"How do you rearrange them in alphabetical order, such as ""Aoki,"" ""Ono,"" and ""Sato""?" Do you have it?

 class person:NSObject {

    var name —NSString?

    init(nam:NSString){

    name=nam
    }

}


var person1 = person(nam: "Ono")
var person2 = person(nam: "Sato")
var person3 = person(nam: "Aoki")

println (person1.name)
println (person2.name)
println (person3.name)

Is it possible for an array with such an instance?

swift

2022-09-30 11:13

1 Answers

You can do it like this.

 var strings=["Sato", "Aoki", "Ono", "Kamikido", "Suzuki"]
sort(string) {str1, str2 instr1>str2}

strings.sort {(lhs,rhs) in return lhs<rhs}

http://qiita.com/mst/items/b18e9531ac0cbdf2f3c3

Edit

class person{

    var name —NSString

    init(nam:NSString){

        name=nam
    }

}


var person1 = person(nam: "Ono")
var person2 = person(nam: "Sato")
var person3 = person(nam: "Aoki")

var people —Array<person>=[ ]


people+=[person1]
people+=[person2]
people+=[person3]

var sortedPeople=people.sorted({($0.name as?) String) <($1.name as? String)})


println (person1.name)
println (person2.name)
println (person3.name)

println(sortedPeople[0].name)
println(sortedPeople[1].name)
println (sortedPeople[2].name)

If you want to use katakana, you can do it like this.

extension String {
    funchiragana()->String{
        var str=""
        for sin unicodeScalars {
            if c.value>=0x30A1&c.value<=0x30F6{
                str.append (UnicodeScalar(c.value-96))
            } else{
                str.append(c)
            }
        }
        return str
    }
}
class person {

    var name —NSString

    init(nam:NSString){

        name=nam
    }

}


var person1 = person(nam: "Ono")
var person2 = person(nam: "Sato")
var person3 = person(nam: "Aoki")
var person4 = person(nam: "Kamikido")

var people —Array<person>=[ ]


people+=[person1]
people+=[person2]
people+=[person3]
people+=[person4]

var sortedPeople=people.sorted({($0.name as String).hiragana()<($1.name as String).hiragana()})


println(person1.name) // Most
println(person2.name) // _yomi
println(person3.name) // Aoki
println(person4.name)// Kamikido

println (sortedPeople[0].name) // Blue
println(sortedPeople[1].name) // Most
println (sortedPeople[2].name) // Kamikido
println (sortedPeople[3].name) // _yomi


2022-09-30 11:13

If you have any answers or tips


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