I was told that in order to treat a one-dimensional array as a two-dimensional array, it is a width × row position + column position, but I am not sure.

Here's the code.

```
var SIDE_CELLS=5;// Width
var COLUMN_CELLS=3;// Vertical Width
varci = new Array (SIDE_CELLS*COLUMN_CELLS);
var row=';
for(varz=0;z<ci.length;++z){
ci[z] = z+1;
row=row+(ci[z]<10?':')+ci[z];
}
console.log(row);
for(vary=0;y<COLUMN_CELLS;++y){
row=';
for (varx=0;x<SIDE_CELLS;++x){
varz=y*SIDE_CELLS+x;
row=row+(ci[z]<10?':')+ci[z];
}
console.log(row);
}
```

The code `varz=y*SIDE_CELLS+x;`

appears to be a two-dimensional array.
I'm weak-headed, so I don't know.

Even if I try to think about it as shown in the picture, I can't grasp the image at all.

I've been thinking about it for two days. Please help me.

2022-09-30 11:27

`varz=y*SIDE_CELLS+x;`

is the index (addressed).

3x5 array

```
[
[1,2,3,4,5], // row: 0, the first column of row 0 contains 2 (0 start)
[6, 7, 8, 9, 10], // row: 1, row 2, column 8
[11, 12, 13, 14, 15] // row:2
]
```

If is a one-dimensional array,

```
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15] It's just a row.
```

The index is

`0,1,2,3,4,5,6,7,8,9,10,11,12,13,14`

Contents: `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 13, 14, 15]`

by the number of columns 5
`{0,1,2,3,4}, {5,6,7,8,9}, {10,11,12,13,14}`

You can see that each has a leading number + {0,1,2,3,4}.

The leading number of each connection is

Row subscripts x columns (i.e., multiple of 5 (number of columns) starting from 0×5, 1×5, 2×5:0) and

You can see that {0,1,2,3,4} is a column subscript.

So,

`Secondary Array [line subscripts][Column subscripts] `

is the first array [column subscripts x columns + column subscripts]

(that is, the secondary array [1][2] is the same (pointing to 8) as the primary array [1×5+2])

You can see that there is a connection.

2022-09-30 11:27

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